QUIZ UPDATED 1Z0-071 - EXAM DISCOUNT ORACLE DATABASE SQL VOUCHER

Quiz Updated 1z0-071 - Exam Discount Oracle Database SQL Voucher

Quiz Updated 1z0-071 - Exam Discount Oracle Database SQL Voucher

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Oracle 1z0-071 (Oracle Database SQL) Exam is a certification exam designed for IT professionals who want to demonstrate their expertise in SQL programming language and Oracle database. 1z0-071 exam is part of the Oracle Certified Associate (OCA) certification program and is an essential requirement for professionals who want to become Oracle certified professionals. 1z0-071 exam covers a wide range of topics, including SQL statements, data manipulation, database objects, and data control language.

The Oracle 1z0-071 exam covers a range of topics such as SQL SELECT statements, data manipulation, data control language, data definition language, and transaction control statements. Candidates are required to have a good understanding of SQL syntax, database objects, data modeling, and normalization concepts. 1z0-071 Exam also tests the candidate's ability to write efficient and optimized SQL queries that can retrieve and manipulate data from the Oracle database. Candidates who pass the exam can demonstrate their ability to design, implement and manage Oracle databases, which can help them advance their careers in the field of database management.

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Oracle Database SQL Sample Questions (Q138-Q143):

NEW QUESTION # 138
Examine the description of the CUSTOMERS table:

Which two SELECT statements will return these results:
CUSTOMER_ NAME
--------------------
Mandy
Mary

  • A. SELECT customer_ name FROM customers WHERE customer_ name KIKE .*Ma*';
  • B. SELECT customer_ name FROM customers WHERE customer_ name LIKE ' % a % ' ;
  • C. SELECT customer_ name FROM customers WHERE customer name LIKE 'Ma*';
  • D. SELECT customer_ name FROM customers WHERE UPPER (customer name) LIKE 'MA&';
  • E. SELECT customer_ name FROM customers WHERE UPPER (customer_ name ) LIKE 'MA*. ;
  • F. SELECT customer_ name FROM customers WHERE customer_ name='*Ma*';
  • G. SELECT customer_ name FROM customers WHERE customer name LIKE 'Ma%' ;

Answer: B,G


NEW QUESTION # 139
Examine the description of the CUSTOMERS table:

Which three statements will do an implicit conversion?

  • A. SELECT FROM customers WHERE insert date = '01-JAN-19';
  • B. SELECT * FROM customers WHERE customer id = '0001';
  • C. SELECT * FROM customers WHERE TO_ CHAR (customer_ id) = '0001';
  • D. SELECT * FROM customers WHERE customer_ id = 0001;
  • E. SELECT. FRON customers WE TO DATE (Insert _ date) = DATE '2019-01-01';
  • F. SELECT. FROM customers WHERE insert_ date = DATE *2019-01-01';

Answer: A,B,F

Explanation:
* A: No implicit conversion is done here because TO_CHAR is an explicit conversion from a numeric to a string data type.
* B: Implicit conversion happens here because the '0001' string will be automatically converted to a numeric data type to match the CUSTOMER_ID field.
* C: No implicit conversion is needed because 0001 is already a numeric literal.
* D: Implicit conversion occurs here because the string '01-JAN-19' will be converted to a date type to compare with INSERT_DATE.
* E: No implicit conversion; DATE is explicitly specified using the DATE keyword.
* F: Incorrect syntax, it has typographical errors and also TO_DATE is an explicit function, not an implicit conversion.
References for SQL functions, conversions, and the CROSS JOIN behavior can be found in the Oracle Database SQL Language Reference 12c documentation.


NEW QUESTION # 140
Examine these statements and results
SQL> SELECT COUNT(*) FROM emp
COUNT(*)
---------------------
14
sQL> CREATE GLOBAL TEMPORARY TABLE t emp As SELECT * FROM emp;
Table created
SQL> INSERT INTo temp SELECT * FROM emp;
14 rows created
SQL> COMMIT:
Commit complete*
SQL> INSERT INTo temp SELECT * EROM emp;
14. rows created
SQL> SELECT COUNT(*) FROM t emp
How many rows are retrieved by the last query?

  • A. 0
  • B. 1
  • C. 2
  • D. 3

Answer: D

Explanation:
Global temporary tables in Oracle Database are designed to hold temporary data for the duration of a session or a transaction.
Given that the global temporary table is created and then populated twice from the emp table without any mention of data deletion, one would initially think the count would be 28, since 14 rows are inserted twice.
However, if the temporary table was created with the default ON COMMIT DELETE ROWS option, the rows are deleted at the end of the transaction, which is signified by the COMMIT operation.
Thus, after the first COMMIT, the temporary table would be empty. After the second INSERT, another 14 rows would be added. So, the last query would retrieve 14 rows unless a DELETE operation was committed.


NEW QUESTION # 141
Which statement will return the last sequence number generated by the EMP_ SEQ sequence?

  • A. SELECT emp_ seq. CURRVAL FROM DUAL;
  • B. SELECT CURRVAL FROM emp_ seq;
  • C. SELECT NEXTVAL FROM emp_ seq;
  • D. SELECT emp_ seq . NEXTVAL FROM DUAL;

Answer: D


NEW QUESTION # 142
You want to display 5 percent of the rows from the SALEStable for products with the lowest AMOUNT_SOLD and also want to include the rows that have the same AMOUNT_SOLDeven if this causes the output to exceed 5 percent of the rows.
Which query will provide the required result?

  • A. SELECT prod_id, cust_id, amount_sold
    FROM sales
    ORDER BY amount_sold
    FETCH FIRST 5 PERCENT ROWS ONLY WITH TIES;
  • B. SELECT prod_id, cust_id, amount_sold
    FROM sales
    ORDER BY amount_sold
    FETCH FIRST 5 PERCENT ROWS WITH TIES;
  • C. SELECT prod_id, cust_id, amount_sold
    FROM sales
    ORDER BY amount_sold
    FETCH FIRST 5 PERCENT ROWS ONLY;
  • D. SELECT prod_id, cust_id, amount_sold
    FROM sales
    ORDER BY amount_sold
    FETCH FIRST 5 PERCENT ROWS WITH TIES ONLY;

Answer: B


NEW QUESTION # 143
......

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